Find x so that x, x+2,x+6 are consecutive terms of a geometric progression
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as x,x+2,x+6
are in Gp
then
(x+2)/x=(x+6)/(x+2)
(x+2)^2=(x+6)x
x^2+2x+4= x^2 +6x
we get
2x +4=6x
4=4x
by dividing with 4
we get x=1
are in Gp
then
(x+2)/x=(x+6)/(x+2)
(x+2)^2=(x+6)x
x^2+2x+4= x^2 +6x
we get
2x +4=6x
4=4x
by dividing with 4
we get x=1
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