Question

Find x so that x,x+2,x+6 are consecutive terms of a gp

Answer 1

this is Ur required result

Answer 2

Answer:

The value of x is 2.

Step-by-step explanation:

If a,b and c are in GP, then

$b^2=ac$

It is given that x,x+2,x+6 are consecutive terms of a gp, then

$(x+2)^2=x(x+6)$

$x^2+4x+4=x^2+6x$

$x^2+4x+4-x^2-6x=0$

$-2x+4=0$

$-2x=-4$

$x=2$

Therefore, the value of x is 2.