Find x so that x,x+2,x+6 are cosicutive terms
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a=x
a2=x+2
a3=x+6
a2=a+d
x+2=x+d (substituting value of a)
x-x+2=d
d=2
a3=2a+d
x+6=2x+2 (substituting value of a and d)
6-2=2x-x
Hence,x=4
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