find x so that x,x+2,x+b are consecutive terms of geometric progression
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(x+2)² = x(x+b)
x² + 4 + 2×x×2 = x² + bx
x² + 4 + 4x = x² + bx
4+4x = bx
4x-bx = -4
x(4-b) = -4
x = -4 / 4-b
x² + 4 + 2×x×2 = x² + bx
x² + 4 + 4x = x² + bx
4+4x = bx
4x-bx = -4
x(4-b) = -4
x = -4 / 4-b
Anonymous:
if three terms are in GP then , a,b,c , then b² = ac
okkk thankc
;) anytym
can u help me for another question
umm.. yes , but later time
okk i will givr question
ohk...
find the 12th term of gp whose 8th term is 192 and common ratio is 2
8th term will be , ar^7 = 192 , r = 2 , calculate a & 11th term will be ar^10
how you gave previous ans step by step like that you gibe know plz
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