Question

find x square plus ysquare, if (xplusy) =14 and xy=48​

Answer 1

Hey friend..!! here's your answer

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x + y. = 14 _________(1)

xy = 48 ___________(2)

Fron equation 1)

x = 14 - y ___________(3)

Put the value of eq 3 in eq. 2

(14 - y)y = 48

14y - {y}^{2} = 48

- {y}^{2} + 14y = 48

{y}^{2} - 14y + 48 = 0

{y }^{2} - 8y - 6y + 48 = 0

y(y - 8) - 6(y - 8) = 0

(y - 8)(y - 6) = 0

y = 6 or 8

Put the value of y in eq 3

x = 14 - 6 or x = 14 - 8

x = 8 or 6

So that the value of x is 8 or 6 and value of y is 6 or 8

xx + yy

(8)(8) + (6)(6)

= 64 + 36

= 100

Or

(6)(6) + (8)(8)

= 36 + 64

= 100

So that the answer is 100

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#Hope its help

Answer 2

Answer:

x^2+y^2=100

Step-by-step explanation:

(x+y)^2 = x^2 + y^2 + 2xy

(14)^2 = x^2+y^2+2×48 (bec. x+y=14 and xy = 48)

196= x^2+y^2 + 96

x^2+y^2 = 100