find x square plus ysquare, if (xplusy) =14 and xy=48
Answers
Answered by
0
Hey friend..!! here's your answer
________________________
x + y. = 14 _________(1)
xy = 48 ___________(2)
Fron equation 1)
x = 14 - y ___________(3)
Put the value of eq 3 in eq. 2
(14 - y)y = 48
14y - {y}^{2} = 48
- {y}^{2} + 14y = 48
{y}^{2} - 14y + 48 = 0
{y }^{2} - 8y - 6y + 48 = 0
y(y - 8) - 6(y - 8) = 0
(y - 8)(y - 6) = 0
y = 6 or 8
Put the value of y in eq 3
x = 14 - 6 or x = 14 - 8
x = 8 or 6
So that the value of x is 8 or 6 and value of y is 6 or 8
xx + yy
(8)(8) + (6)(6)
= 64 + 36
= 100
Or
(6)(6) + (8)(8)
= 36 + 64
= 100
So that the answer is 100
_____________
#Hope its help
Answered by
1
Answer:
x^2+y^2=100
Step-by-step explanation:
(x+y)^2 = x^2 + y^2 + 2xy
(14)^2 = x^2+y^2+2×48 (bec. x+y=14 and xy = 48)
196= x^2+y^2 + 96
x^2+y^2 = 100
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