find X such that 125/8*125/8powerX=5/2power 18
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125/8 × (125/8)^x = (5/2)^18
(5/2)³×[(5/2)^3]^x = (5/2)^18
(a^m)^n = a^mn
(5/2)^3 × (5/2)^3x = (5/2)^18
a^m × a^n = a^m+n
=> (5/2)^3+3x = (5/2)^18
=> as bases are equal exponents are equal
=> 3+3x = 18
=> 3x = 15 => x = 15/3 = 5
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