Question

find x such that 3upon 5 ki power 3 multiply by3upon5 ki power -6 =3upon 5 ki power 2x-1​

Answer 1

Answer: -1

See in the image attached

Hope it helps

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Answer 2

- 1

Step-by-step explanation:

Given:

${(\dfrac{3}{5})}^{3} \times {( \dfrac{3}{5}) }^{ - 6} = {( \dfrac{3}{5}) }^{(2x - 1)}$

To Find:

The value of x

How to Solve:

Basically This question is related to Laws of Indices.

1. Laws of Indices will be use.

2. Add or Subtract the power if They are in multiple or division.

3. Eliminate the same base from both side

4. Just Solve as a Equation and get answer

Solution:

See in the attachment.

${\boxed{\red{\textsf{Some Important Laws of Indices}}}}$

${a}^{n}.{a}^{m}={a}^{(n + m)}$

${a}^{-1}=\dfrac{1}{a}$

$\dfrac{{a}^{n}}{ {a}^{m}}={a}^{(n-m)}$

${({a}^{c})}^{b}={a}^{b\times c}={a}^{bc}$

${a}^{\frac{1}{x}}=\sqrt[x]{a}$

$a^0 = 1$

$[\text{where all variables are real and greater than 0}]$