Question

Find x such that : (7/4)^-3 × (7/4)^-5 = (7/4)^x-2

Answer 1

Answer:

value of x is 18

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Answer 2

ʕ•ﻌ•ʔ$\huge\bold\pink{hello!!!}$ʕ•ﻌ•ʔ

HERE IS UR ANSWER

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$( \frac{7}{4} ) {}^{ - 3} \times (\frac{7}{4} ) {}^{ - 5} = (\frac{7}{4} ) {}^{x - 2}$

$( \frac{7}{4} ) {}^{ - 3 - 5} = (\frac{7}{4}) {}^{x - 2} \\ - 3 - 5 = x - 2 \\ - 8 = x - 2 \\ x = - 8 + 2 \\ x = - 6$

since bases are same powers will be added.