Find x such that x(x+6)=27
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A question of quadric equation...ooh I messed the chance...
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X^2+6x=27
X^2+6x-27=0
X^2+9x-3x-27=0
X(x+9)-3(x+9)=0
(X+9)(x-3)=0
X=-9,x=3
Value of x=-9&3
Hope it's help you friend ☺️
X^2+6x-27=0
X^2+9x-3x-27=0
X(x+9)-3(x+9)=0
(X+9)(x-3)=0
X=-9,x=3
Value of x=-9&3
Hope it's help you friend ☺️
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1
Hope it Helps.....☺...
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