find x. the options are given
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no option is correct
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option (C) X = 4
the value of log7(X) will be equal to zero , if X=1
here X is log5(√x2+x+5)
therefore
log5(√x2+x+5) = 1
and this value will be equal to 1 , only
√X2+X+5 = 5 (it should be equal to base)
squaring on b.s
X2+X+5 = 25
X2+X-20=0
X2+5X-4X-20=0
so , X= -5 or X= 4
from the options , X=4 is present. so it's d answer
the value of log7(X) will be equal to zero , if X=1
here X is log5(√x2+x+5)
therefore
log5(√x2+x+5) = 1
and this value will be equal to 1 , only
√X2+X+5 = 5 (it should be equal to base)
squaring on b.s
X2+X+5 = 25
X2+X-20=0
X2+5X-4X-20=0
so , X= -5 or X= 4
from the options , X=4 is present. so it's d answer
KNIGHTSTER:
how?
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