Question

FIND X........TRIAGLES

Answer 1

See the attach file for ans

Answer 2

Hii...
Here's your answer-

Given: BD= AD= CD

To Find: x

Solution: BD=AD (given)
Therefore, angle DBA = angle DAB( Angles opposite to equal sides are equal)
HENCE, angle DAB= 48 degree

In triangle ABD,
angle ADB+angle DAB+ angle DBA= 180 degree ( Angle sum property)

Therefore, angle ADB + 48 +48 = 180 DEGREE
angle ADB + 96= 180 DEGREE
angle ADB = 180- 96 = 84 DEGREE

AD = CD ( Given)
Therefore, angle DAC = angle DCA
Hence, angle DCA = x

angle ADB= angle DAC + angle DCA ( EXTERIOR ANGLE PROPERTY)

angle ADB= x+ x
84 = 2x
x= 84/ 2
x = 42 degree

HOPE IT HELPS...

Thanks :)