Question

find x using transposition method (x^2+16) +(x^2-16)=2x(x-5)+8​

Answer 1

Step-by-step explanation:

$({x}^{2} + 16) + ({x}^{2} - 16) = 2x(x - 5) + 8$

${2x}^{2} = 2 {x}^{2} - 10x + 8$

$10x = 8$

$x = \frac{8}{10}$