Question

find x valu
3x[(-6)+x]=3x(-6)+3x10
​

Answer 1

The given expression is

$3x[(-6)+x]=3x(-6)+3\times 10$

We have to find the value of $x$

so,

$3x[(-6)+x]=3x(-6)+3\times 10$

$-18x+3x^{2}=18x+30\\-18x+3x^{2}+18x=30$

As there is one plus and one minus cancelled

                        $3x^{2} =30$

  Dividing both side by 3,we get

                          $x^{2} =10$

When the square shift to right it becomes square root

                     ∴    $x=\sqrt{10}$

square root of 10 is 3.12

Answer 2

Answer:

The given expression is

We have to find the value of

so,

As there is one plus and one minus cancelled

                       

 Dividing both side by 3,we get

                         

When the square shift to right it becomes square root

                    ∴    

square root of 10 is 3.12