find x when -3/4 of power x+1 ÷ -3/4 of power -3=3/4 to the power 4
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Hi ,
( -3/4 )^x+1 / ( -3/4 )^-3 = ( 3/4 )⁴
[( - 3/4 )^x ( -3/4 )¹ ]/( - 3/4 )^-3 = ( 3/4 )⁴
( -3/4 )^x / ( -3/4 )-4 = ( 3/4 )⁴
( -3/4 )^x = ( 3/4 )⁴ ( - 3/4 )^-4
( - 3/4 )^x = ( 3/4 )⁴ ( 3/4 )^-4
( -3/4 )^x = ( 3/4 )⁴ ( 4/3 )⁴
( - 3/ 4 )^x = [ ( 3 × 4 )/(4 × 3 ) ]⁴
( -3/4 )^x = 1⁴
( - 3/4 )^x = ( - 3/4 )^0
[ since a^0 = 1 ]
x = 0
[ since if a^n = a^m then n = m ]
Therefore ,
x = 0
I hope this helps you.
: )
( -3/4 )^x+1 / ( -3/4 )^-3 = ( 3/4 )⁴
[( - 3/4 )^x ( -3/4 )¹ ]/( - 3/4 )^-3 = ( 3/4 )⁴
( -3/4 )^x / ( -3/4 )-4 = ( 3/4 )⁴
( -3/4 )^x = ( 3/4 )⁴ ( - 3/4 )^-4
( - 3/4 )^x = ( 3/4 )⁴ ( 3/4 )^-4
( -3/4 )^x = ( 3/4 )⁴ ( 4/3 )⁴
( - 3/ 4 )^x = [ ( 3 × 4 )/(4 × 3 ) ]⁴
( -3/4 )^x = 1⁴
( - 3/4 )^x = ( - 3/4 )^0
[ since a^0 = 1 ]
x = 0
[ since if a^n = a^m then n = m ]
Therefore ,
x = 0
I hope this helps you.
: )
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