Find x,where DC=4cm,bc=16cm and ac=x cm
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BC=BD+ DC. ( B-D-C)
16=BD +4
16-4= BD
BD = 12
by geometric mean theorem
AD2 = BD ×DC
AD2 = 12× 4
AD2 = 48
AD = √48
AD = √16×3
AD= 4√3 units
in ∆ADC
/_ D = 90
by Pythagoras theorem
AC2 = AD2+ DC2
X2 = (4√3)2 + (4)2
X2 = 16×3+ 16
X2 = 48+16
X2= 64
x = √64
x= 8 units
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