find X
|| X - 1|+2|=1
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Answer:
x is not exist
Step-by-step explanation:
let x>1 then modules will open positive
|x-1 +2| = 1
|x+1|=1
x+1 =1
x=0 before we assume x>1 then it is contradictory.
let x<1 then modules will open negetive
| -(x-1) +2 | = 1
| -x+1+2 | = 1
so |-x+3| = 1
now, -x+3 = 1
x = 3-1 = 2
again it is contradiction..
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