Question

Find x

[(x+1)(4x-3)-4x+5]/4x+1 =2

Answer 1

$\frac{(x + 1)(4x - 3) - 4x + 5}{4x + 1} = 2 \\ \frac{ {4x}^{2} - 3x + 4x - 3 - 4x + 5 }{4x + 1} = 2 \\ \frac{ {4x}^{2} - 3x + 2}{4x + 1} = 2 \\ {4x}^{2} - 3x + 2 = 8x + 2 \\ {4x}^{2} - 11x = 0 \\ x(4 x - 11) = 0 \\ x = 0 \\ 4x - 11 = 0 \\ x = \frac{11}{4}$
your answer is here ✌✌✌