Question

find
x

x – ax²+ 6x -a
the remainder when
divided
by x-a​

Answer 1

Answer:

Here,(x) = xa²+6x-a, and the zero of x-a is a

So, (a)=a×a²+6×a-a

=2a² + 5a

So, by the Remainder theorem,

2a²+5a is the Remainder when x + ax²+6x-a is divided by x-a.

hope you understand