Question

find x: x2-3 √5x+10=0

Answer 1

Given:-

➜p(x)=x²-3√5x+10

$\rule{200}{1}$

To Find:-

✪The Value of x?

$\rule{200}{1}$

AnsWer:-

☞x=√5

☞x=2√5

$\rule{200}{1}$

➜x²-3√5x+10=0

♦S=-3√5→[Sum of Equation]

♦P=10→[Product of Equation]

★-2√5+(-√5)=-3√5→S

★-2√5×√5=10→P

↝x²-2√5x-√5x+10=0

↝x(x-2√5)-√5(x-2√5)=0

➜x-√5=0

☞x=√5

➜x-2√5=0

☞x=2√5

$\rule{200}{2}$

Answer 2

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$\huge\tt{GIVEN:}$

• A polynomial x2-3 √5x+10=0

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$\huge\tt{</strong><strong>TO~</strong><strong>F</strong><strong>I</strong><strong>N</strong><strong>D</strong><strong>:</strong><strong>}$

• VALUE OF X

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$\huge\tt{</strong><strong>SOLU</strong><strong>TION</strong><strong>:}$

In the equation,x²-3√5x+10=0

↪-2√5+(-√5)=-3√5

↪-2√5×√5=10

✡Sum of Equation = -3√5

✡Product of Equation = 10

Then, by comparing both we get,

↪x²-2√5x-√5x+10=0

↪x(x-2√5)-√5(x-2√5)=0

↪x-√5=0

↪x=√5

↪x-2√5=0

↪x=2√5

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