Question

Find x:
x²+5x²-(a²+a-6)=0

Answer 1

Answer:

Hope it helps you

Thank you ☺️

Answer 2

x2+5x-(a2+a-6)=0

x2+5x-(a2+3a-2a-6)=0

→x2+5x-(a(a+3)−2(a+3))=0

›x2+5x-(a+3)(a-2)=0

→x2+[(a+3)-(a-2)]x-(a+3)(a−2)=0

→x2+(a+3)x-(a−2)x-(a+3)(a−2)=0

→x[x+(a+3)]-(a−2)[x+(a+3)]=0

→[x+(a+3)][x-(a−2)]=0

→ [x+(a+3)]=0 or [x-(a-2)]=0

⇒x=-(a+3) or x=(a-2)