Find x, y and O in the following figure
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x=108, y=144 ok o= 216 I hope it will help
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In ∆AOB
OA=OB (Both are radii of same circle)
Therefore,
Angle OBA =Angle OAB = 15°
(Angles opposite to equal sides are equal)
In ∆AOC
OA=OC (Both are radii of same circle)
Therefore,
Angle OCA =Angle OAC = 21°
(Angles opposite to equal sides are equal)
Angle A (x) = Angle OAB + Angle OAC
x = 15° + 21° = 36°
As O is the centre of the circle,
Angle BOC = 2×Angle BAC
(Angle at the centre is twice the angle at the circumference)
y = 2x
y = 2×36°= 72°
- x = 36°
- y = 72°
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