Question

Find x,y and z given that the numbers x,10,y,24,z are in AP

Answer 1

Solution :Since the given sequence is arithmetic progression,t2 - t1 = 10 - x ---(1)t3 - t2 = y - 10 ---(2)t4 - t3 = 24 - y ---(3)t5 - t4 = z - 24 ---(4)(1) = (2)10 - x = y - 10x + y = 20(2) = (3)y - 10 = 24 - yy + y = 24 + 102y = 34y = 17

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Answer 2

Answer: x=3, y=17, z=31

Step-by-step explanation:

Since x, 10, y, 24, z are in AP,

    24 - y = y - 10

⇒  2y = 34

⇒  y = 17

∴, commom diffrence = 24 - 17 = 7

So, the values are x = 10 - 7 = 3

                              y = 17

                              z = 24 + 7 = 31