Find x, y and z in the following figures.
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Answered by
1
Answer:
hope it helps you!!
Step-by-step explanation:
In ∆ABC,
we know that, x + 50° + 40° = 180°
=> x = 180° - 90°
=> x = 90°
now, we know that
x + y = 180(linear pair)
=> 90° + y = 180°
=> y = 180° - 90° =90°
and In ∆ ABD
y + z + 28° = 180°
=> 90° + z + 28°= 180°
z = 180° - 118°
= 62°
Answered by
1
Answer:
x = 90°
y = 90°
z = 62°
Step-by-step explanation:
angle ABC = 50°
angle ACB = 40°
angle ABC + angle ACB + angle BAC = 180° by angle sum property
50°+40°+x=180°
90° + x = 180°
x = 180 - 90
x = 90°
angle x + angle y = 180° by linear pair
90 + y = 180
y = 180-90
y = 90°
angle DBA + angle DAB + angle z = 180° by angle sum property of a triangle
28 + y + z = 180
28 +90 + z = 180
118 + z = 180
z = 180 - 118
z = 62°
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