Question

Find X , Y and Z in the following figures
plz give answer​

Answer 1

Answer:

∠x = 50

∠y = 130°

∠z = 20°

Step-by-step explanation:

In ΔABC

∠x = 180 - 70+60 (Angle Sum Property of a Δ)

= 180 - 130

∠x = 50°

∠x and ∠y are in linear pair

∴180 - ∠x

∠y = 180° - 50° = 130°

In ΔACD

∠z = 180 - 30+130 (∠y = 130°)

∴∠z = 180 - 160 = 20°

Answer 2

Answer :

• x = 50
• y = 130
• z = 20

Concepts insight :

Angle sum property :

• The sum of all angles of a triangle is 180°

Linear pair property :

• Angles in a straight line add up to 180° / are supplementary

Solution :

In triangle ABC we have ,

• Angle BAC = 60°
• Angle ABC = 70°
• Angle ACB = x

Thus by angle sum property we get ,

• Angle BAC + Angle ABC + Angle ACB = 180
• 60 + 70 + x = 180
• 130 + x = 180
• x = 180 - 130
• x = 50°

Solving for value of y ,

By linear pair property we can say that ,

• Angle ACB + Angle ACD = 180°
• x + y = 180
• Put the value of x from first part that is 50
• 50 + y = 180
• y = 180 - 50
• y = 130°

Solving for value of z ,

In triangle ACD we have ,

• Angle DAC = 30°
• Angle ADC = z
• Angle ACD = 130

Therefore by angle sum property we get ,

• Angle DAC + Angle ADC + Angle ACD = 180
• 30 + z + 130 = 180
• 160 + z = 180
• z = 180 - 160
• z = 20°