Math, asked by studentuser12345, 4 months ago

find x:y if 15(x²+y²)-34xy=0​

Answers

Answered by GaneshRM2006
1

Answer:

15(x²+y²)-34xy=0​

15x²+15y²-34xy=0

15x²-9xy-25xy+15y²=0

3x(5x-3y)-5y(5x+3y)=0

(3x - 5y)(5x + 3y)=0

3x-5y = 0  or 5x+3y = 0

3x = 5y       or  5x = -3y

x/y = 5/3     or   x/y = -3/5

x:y = 5:3     or  -3:5

the more accurate answer is 5:3 as negative values are not seen in ratios.

Similar questions