Question

Find [x+y]÷[x-y] if
i) x=5/2,y=-3/4​

Answer 1

Answer:

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Step-by-step explanation:

$x = \frac{5}{2},\: \:y = \frac{ - 3}{4} \\ \\ \\ \\ x + y = \frac{5}{2} + \frac{ - 3}{4} \\ \\ taking \:\: lcm \\ \\ x + y = \frac{5 \times 2}{2 \times 2} + \frac{ - 3}{4} \\ \\ x + y = \frac{10}{4} + \frac{ - 3}{4} \\ \\ x + y = \frac{10 + ( - 3)}{4 } \\ \\ x + y = \frac{10 - 3}{4} \\ \\ x + y = \frac{7}{4} \\ \\ \\ \\ x - y = \frac{5}{2} - (\frac{ - 3}{4} )\\ \\ taking \: \:lcm \\ \\x - y = \frac{5 \times 2}{2 \times 2} - ( \frac{ - 3}{4}) \\ \\ x - y = \frac{10}{4} - ( \frac{ - 3}{4}) \\ \\x - y = \frac{10 - ( -3 )}{4} \\ \\ x - y = \frac{10 + 3}{4} \\ \\ x - y = \frac{13}{4} \\ \\ \\ \\ Now, \\ [x+y]÷[x-y] = \frac{7}{4} \div \frac{13}{4} \\ \\ [x+y]÷[x-y] = \frac{7}{4} \times \frac{4}{13} \\ \\ [x+y]÷[x-y] = \frac{7}{\cancel{4}} \times \frac{\cancel4}{13} \\ \\ [x+y]÷[x-y] = \frac{7}{13}$