Question

find (x+y) ÷(x-y) if x= 1/4 y=3/2​

Answer 1

Answer:

x=

4

1

and,

y =\frac{3}{2}y=

2

3

To find:

The value of \frac{x+y}{x-y}

x−y

x+y

= ?

Solution:

⇒ \frac{x+y}{x-y} =\frac{\frac{1}{4} +\frac{3}{2} }{\frac{1}{4} -\frac{3}{2} }

x−y

x+y

=

4

1

−

2

3

4

1

+

2

3

By taking L.C.M, we get

=\frac{\frac{1+6}{4} }{\frac{1-6}{4} }=

4

1−6

4

1+6

=\frac{1+6}{1-6}=

1−6

1+6

=-\frac{7}{5}=−

5

7

Thus, the correct answer is "-\frac{7}{5}−

5

7

".

Answer 2

Answer:

Answer is -7/5

Step-by-step explanation:

x = 1/4, y = 3/2

or, (x+y)÷(x-y)

= (1/4 + 3/2) ÷ (1/4 - 3/2)

LCM of 2 and 4 is 4

= (1/4 + 6/4)÷(1/4 - 6/4)

= 7/4 ÷ -5/4

= 7/4 × -4/5

= -7/5

Hope it helps.

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