Question

Find (x+y) +(x-y)if:x=1/8,y=9/5

Answer 1

$x = \frac{1}{8} \\ \\ y = \frac{9}{5}$

Now,

$(x + y) + (x - y) \\ \\ ( \frac{1}{8} + \frac{9}{5} ) + ( \frac{1}{8} - \frac{9}{5} ) \\ \\ ( \frac{5 + 72}{40} ) + ( \frac{5 - 72}{40} ) \\ \\ \frac{77}{40} + ( \frac{ - 67}{40} ) \\ \\ \frac{77 + ( - 67)}{40} = \frac{77 - 67}{40} = \frac{10}{40} \\ \\ { \boxed {\boxed {\boxed {\huge{\frac{1}{4} }}}}}$

$<marquee>MARK BRAINLIEST$