Find X, y, z, given that the numbers X, 10,y,24,z are in a. P.
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1
Solution :
Since the given sequence is arithmetic progression,
t2 - t1 = 10 - x ---(1)
t3 - t2 = y - 10 ---(2)
t4 - t3 = 24 - y ---(3)
t5 - t4 = z - 24 ---(4)
(1) = (2)
10 - x = y - 10x + y = 20(2) = (3)y - 10 = 24 - yy + y = 24 + 102y = 34y = 17
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Answer:
x=45.67.87.56,11is this are answer
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