Math, asked by subhan34291, 4 months ago

find x:y:z if x:y=4/3:5/4,x:y=6:3/4​

Answers

Answered by bson
4

Step-by-step explanation:

x:y = 4/3 : 5/4 = 16/12: 15/12 =16:15

y represents 15 parts

y:z= 6: 3/4 = 24:3

y represents 24

lcm of 15,24 =120

x:y = 16×8:15×8 = 128:120

y:z= 24×5:3×5=120:15

x:y:z = 128:120:15

Answered by bhowmik2018piu
3

Answer:

x:y:z= 128:120:15

Step-by-step explanation:

x:y=4/3:5/4

x:y= 16:15

I think it y:z=6:3/4 not x:y= 6:3/4

y:z= 6:3/4

y:z= 24:3= 8:1

so

x:y = 16:15 = 16*8:15*8 = 128:120

y:z= 8:1 = 8*15:1*15= 120: 15

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x:y:z= 128:120:15

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