Question

find x,y,z, in the figure //BC
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Answer 1

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$\sf\angle FAE = 70° \\ \sf \angle ACD = 110°$

vertically opposites angles are equal.

$\sf \angle x = \angle FAE \\ \sf \implies \angle x = 70°$

BCD has a straight line.

$\angle ACB + \angle ACD = 180° \\ \angle Z = 180°-110° \\ \angle Z = 70° \\ \sf {\tt{In \: \triangle ABC,}}$

$\angle X + \angle Y + \angle Z = 180° \\ \implies 70°+ \angle Y + 70° = 180° \\ \implies \angle Y + 140°=180° \\ \implies \angle Y = 180° -140° \\ \implies \angle Y = 40°$