find x y z in the given figure AB is parallel to CD
above figure
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Given :
- ∠BAC = 53°
- ∠BCD = 70°
- AB || CD
To Find :
- x , y and z
Solution :
AB || CD and BC is a transversal.
So, ∠BCD = x = 70° [Alternate Interior Angle]
In △ABC
∠BAC+∠BCD+∠ACB = 180° [Angle Sum Property]
➨ 53° + 70° + ∠ACB = 180°
➨ 123° + ∠ACB = 180°
➨ ∠ACB = 180°- 123°
➨∠ACB = 57°
Therefore, ∠ACB = z = 57°
∠ACE = 180° [ Straight angle ]
➨∠BCD + z + y = 180°
➨ 70° + 57° + y = 180°
➨ 117° + y = 180°
➨ y = 180° - 117°
➨ y = 63°
Hence, x = 70°, y = 63° and z = 57°
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