find x,y,z in the given figure if ab//cd
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here AE is a straight line
so, x+z+ 53=180=> x+z= 127 ......1
here ABC is triangle
so , sum of all angles of triangle is 180
z+y+70=180=> z+y= 110..........2
here AB is parallel to BD
so, y= 53
put y in eq2
z= 110-53=147
put z in eq1
x+147= 127
x= 147-127=20
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