find x,y,z in this figure
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x = 20°
y = 20°
z = 80°
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Answered by
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Answer:
In triangle ADB
angle DBA+angle BAD+angleADB=180°
x+100°+60°=180°
=> x=180°-(100+60)°=180°-160°=20°
again ,
angle DAB+angleBAC=180°
=> 100°+z=180°
=> z=180°-100°=80°
In triangle ABC
angleABC+angle BCA+angle CAB=180°
y+80°+z=180°
=> y=180°-80°-80°
=> y=180°-160°=20°
x=20°, y=20°, z=80°
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