find x y z in this question. please give line by line explanation
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In triangle BAD
ANGLE BDA + ANGLE DAB + ANGLE DBA = 180°(angle sum property)
60° + 100° + x = 180°
x = 180°- 160°
x = 20°
Now,
ANGLE DAB + ANGLE BAC = 180°(linear pair)
100°+z = 180°
z = 180°-100°
z = 80°
Now,
In triangle ABC
ANGLE ABC + ANGLE BCA + ANGLE CAB = 180°(Aangle sum property)
y + 80° + 80 ° = 180°
y = 180°-160°
y = 20°
So, x = 20°
y = 20°
z = 80°
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