Math, asked by dipalbhatt09, 6 months ago

find x+y+z+w in the quadrilateral​

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Answered by Anonymous
5

Answer-:

Since, the sum of the measures of interior angles of a quadrilateral is 360∘

Since, the sum of the measures of interior angles of a quadrilateral is 360∘Also,115∘+70∘+60∘=245∘

Since, the sum of the measures of interior angles of a quadrilateral is 360∘Also,115∘+70∘+60∘=245∘∴∠ABC=360∘−245∘=115∘

Since, the sum of the measures of interior angles of a quadrilateral is 360∘Also,115∘+70∘+60∘=245∘∴∠ABC=360∘−245∘=115∘Now, x=ext∠BCD

Since, the sum of the measures of interior angles of a quadrilateral is 360∘Also,115∘+70∘+60∘=245∘∴∠ABC=360∘−245∘=115∘Now, x=ext∠BCD=180∘−115∘=65∘

Since, the sum of the measures of interior angles of a quadrilateral is 360∘Also,115∘+70∘+60∘=245∘∴∠ABC=360∘−245∘=115∘Now, x=ext∠BCD=180∘−115∘=65∘y=180∘−70∘=110∘

Since, the sum of the measures of interior angles of a quadrilateral is 360∘Also,115∘+70∘+60∘=245∘∴∠ABC=360∘−245∘=115∘Now, x=ext∠BCD=180∘−115∘=65∘y=180∘−70∘=110∘z=180∘−60∘=120∘

Since, the sum of the measures of interior angles of a quadrilateral is 360∘Also,115∘+70∘+60∘=245∘∴∠ABC=360∘−245∘=115∘Now, x=ext∠BCD=180∘−115∘=65∘y=180∘−70∘=110∘z=180∘−60∘=120∘w=180∘−115∘=65∘

Since, the sum of the measures of interior angles of a quadrilateral is 360∘Also,115∘+70∘+60∘=245∘∴∠ABC=360∘−245∘=115∘Now, x=ext∠BCD=180∘−115∘=65∘y=180∘−70∘=110∘z=180∘−60∘=120∘w=180∘−115∘=65∘∴x+y+z+w=65∘+110∘+120∘+65∘=36

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Answered by Anonymous
0

The above answer is correct

as I had written it from another id

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