find x+y+z+w in the quadrilateral
Answers
Answer-:
Since, the sum of the measures of interior angles of a quadrilateral is 360∘
Since, the sum of the measures of interior angles of a quadrilateral is 360∘Also,115∘+70∘+60∘=245∘
Since, the sum of the measures of interior angles of a quadrilateral is 360∘Also,115∘+70∘+60∘=245∘∴∠ABC=360∘−245∘=115∘
Since, the sum of the measures of interior angles of a quadrilateral is 360∘Also,115∘+70∘+60∘=245∘∴∠ABC=360∘−245∘=115∘Now, x=ext∠BCD
Since, the sum of the measures of interior angles of a quadrilateral is 360∘Also,115∘+70∘+60∘=245∘∴∠ABC=360∘−245∘=115∘Now, x=ext∠BCD=180∘−115∘=65∘
Since, the sum of the measures of interior angles of a quadrilateral is 360∘Also,115∘+70∘+60∘=245∘∴∠ABC=360∘−245∘=115∘Now, x=ext∠BCD=180∘−115∘=65∘y=180∘−70∘=110∘
Since, the sum of the measures of interior angles of a quadrilateral is 360∘Also,115∘+70∘+60∘=245∘∴∠ABC=360∘−245∘=115∘Now, x=ext∠BCD=180∘−115∘=65∘y=180∘−70∘=110∘z=180∘−60∘=120∘
Since, the sum of the measures of interior angles of a quadrilateral is 360∘Also,115∘+70∘+60∘=245∘∴∠ABC=360∘−245∘=115∘Now, x=ext∠BCD=180∘−115∘=65∘y=180∘−70∘=110∘z=180∘−60∘=120∘w=180∘−115∘=65∘
Since, the sum of the measures of interior angles of a quadrilateral is 360∘Also,115∘+70∘+60∘=245∘∴∠ABC=360∘−245∘=115∘Now, x=ext∠BCD=180∘−115∘=65∘y=180∘−70∘=110∘z=180∘−60∘=120∘w=180∘−115∘=65∘∴x+y+z+w=65∘+110∘+120∘+65∘=36
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The above answer is correct
as I had written it from another id