find x+y+z+w please help me
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Answered by
1
360°
Step-by-step explanation:
w=180°- [360°-(70°+130°+80°)]} (linear pair)
w=180°- 80°= 100°
x= 180°-130°= 50° (linear pair)
y= 180° -80°= 100° (linear pair)
z= 180° -70° = 110° (linear pair)
to find;
w+x+y+z= 100°+50°+100°+110°
w+x+y+z= 360°
hope it helped u
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Answered by
1
Answer:
In the quadrilateral,
130+80+70+a=360
we take the unknown angle as a
280+a=360
a=360-280
a=80
so now,
130+X=180
x=180-130
x=50
80+y=180
y=180-80
y=100
70+z=180
z=180-70
z=110
a+w=180
80+w=180
w=180-80
w=100
so ,
x+y+w+z
50+100+110+100
=360
Step-by-step explanation:
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