Question

find {(x²+x+1)}² please answer fast​

Answer 1

Answer:

Step-by-step explanation:

I can't answer (x2+x−1)2

But I can solve (x2+x−1)2=0

Now we take the square on both sides….and we get;

x2+x−1=0

Let's solved of x;

(x+12)2−(12)2−1=0

(x2+12)2−54=0

(x+12)2=54

x+12=±5√4

x=−1+5√2 or −1−5√2