Math, asked by sanjanaparida, 6 months ago

find x²+y²+z²+2xy-2yz-2zx,if x=4,y=-5,z=7​

Answers

Answered by gopalpvr
0

Step-by-step explanation:

x=4,y=-5,z=7

x²+y²+z²+2xy-2yz-2zx

=4² + 5² + 7² + 2 * 4 * 5 - 2 * 5 * 7 - 2 * 7 * 4

= 16 + 25 + 49 + 40 - 70 - 56

=4

or

x²+y²+z²+2xy-2yz-2zx= (X+y-z) ²

=(4+5-7) ²

=(2) ²

=4

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