Question

find(x²y²-1)(x²y²) &verify for x=1, y=2​

Answer 1

Step-by-step explanation:

Let base of ∆ = 4x m

and height of ∆ = 5x m

area of ∆ =40 m2

∵ (1/2) base × height = area of ∆

(1/2) × 4x × 5x = 40

10x2 = 40

x2 = 4

x =

x = 2

∴ base = 4x = 4 × 2 = 8 m

height = 5x = 5 × 2 = 10 m

∴ 8 m ; 10 m

Answer 2

$= ( {x}^{2} {y}^{2} - 1)( {x}^{2} {y}^{2})$

$= ( {1}^{2} {2}^{2} - 1)( {1}^{2} {2}^{2} )$

$= (1 \times 4 - 1)(1 \times 4)$

$= (4 - 1)(4)$

$= (3) \times (4)$

$= 12$