Question

find x3+-x2+2x+10 where value of x is 1+√3i​

Answer 1

Given ,

x=1+2i

Putx=1+2i,inx

3

+x

2

−x+22

We get

x

3

+x

2

−x+22=(1+2i)

3

+(1+2i)

2

−(1+2i)+22

=1

3

+8i

3

+3.1

2

2i+3.1.(2i)

2

+(1

2

+4i

2

+4i)+22

=23+8i

3

+16i

2

+10i

Given ,

i= −i=23+8i.i

2

+16i

2

+10i

=23+8i(−1)+16(−1)+10i

=23−8i−16+10i

=7+2i

Answer 2

Answer:

7+2i is the right answer..