Question

find xa nd y by cross multiplication method
q 1​

Answer 1

Answer:

Given equations:-

Given equations:-x2+y3=13andx5−y4=−2

Given equations:-x2+y3=13andx5−y4=−2Let x1=pandy1=q

Given equations:-x2+y3=13andx5−y4=−2Let x1=pandy1=qThus, we have,

Given equations:-x2+y3=13andx5−y4=−2Let x1=pandy1=qThus, we have,2p+3q=13=>2p+3q−13=05p−4q=−2=>5p−4q+2=0

Given equations:-x2+y3=13andx5−y4=−2Let x1=pandy1=qThus, we have,2p+3q=13=>2p+3q−13=05p−4q=−2=>5p−4q+2=0Using cross-multiplication method to solve the equations we have,

Given equations:-x2+y3=13andx5−y4=−2Let x1=pandy1=qThus, we have,2p+3q=13=>2p+3q−13=05p−4q=−2=>5p−4q+2=0Using cross-multiplication method to solve the equations we have,(3)(2)−(−4)(−13)p=(−13)(5)−(2)(2)q=(2)(−4)−(5)(3)16−52p=−65−4q=−8−151−46p=−69q=−23

=>−69q=−231or,q=3Now,p=x1=2=>x=21andq=y1=3=>y=31∴x=21andy=31

Step-by-step explanation:

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