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<A externally is given 92°
so angle BAC is also 92° [vertically opposite angles]
as Ab=Ac
<b = <c = x
in tri abc
a + b + c =180
92 + x + x =180
2x = 88
x = 44°
Angle A + Angle B = y
92 + 44 = y
y = 136°
pls mark as brainiest.......
so angle BAC is also 92° [vertically opposite angles]
as Ab=Ac
<b = <c = x
in tri abc
a + b + c =180
92 + x + x =180
2x = 88
x = 44°
Angle A + Angle B = y
92 + 44 = y
y = 136°
pls mark as brainiest.......
chaobhagabatgogoi98:
Thanks for your answer.
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Hope it helps you
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