Question

find xtz using Cramer,s rule if x+z=4,y+z=2,x+y=0​

Answer 1

Step-by-step explanation:

find xtz using Cramer,s rule if x+z=4,y+z=2,x+y=0

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Answer 2

Question :-

Find xtz using Cramer,s rule if x+z=4,y+z=2,x+y=0.

Answer :-

Given:-

• x + z = 4 => Equation 1
• y + z = 2 => Equation 2
• x + y = 0 => Equation 3

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Equation 1 :-

x + z = 4

Transposing x to the other side,

z = 4 - x

Equation 2 :-

y + z = 2

substituting z for 4-x as derived from equation 1,

y + (4-x) = 2

Equation 3 :-

x + y = 0

Transposing x to the other side,

y = 0 - x

y = (-x)

Substituting y for (-x) in equation 2,

y + 4-x = 2

-x + 4 -x = 2

4 - 2x = 2

Transposing (-2x) to the other side,

4 = 2 + 2x

Transposing 2 to the other side,

4 - 2 = 2x

2 = 2x

Hence,

$\dfrac{2}{2} = x$

$= > 1$

Now that we know the value of x,

y = (-x)

y = (-1)

z = 4 - x

z = 3 (4-1)

Let us find xtz,

x × t × z

=> 1 × t × 3

=> 3t

Hope it helps!

Happy day!