Question

Find xx+yy if x+y=14 and xy=48

Answer 1

xx+yy = (x)^2+(y)^2

now x^2+y^2 = (x+y)^2-2xy


x^2+y^2 = (14)^2 -2*48

x^2+y^2 = 196 - 96

x^2+y^2 =


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Answer 2

Hey friend..!! here's your answer
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x + y. = 14 _________(1)

xy = 48 ___________(2)


Fron equation 1)

x = 14 - y ___________(3)

Put the value of eq 3 in eq. 2

$(14 - y)y = 48 \\ \\ 14y - {y}^{2} = 48 \\ \\ - {y}^{2} + 14y = 48 \\ \\ {y}^{2} - 14y + 48 = 0 \\ \\ {y }^{2} - 8y - 6y + 48 = 0 \\ \\ y(y - 8) - 6(y - 8) = 0 \\ \\ (y - 8)(y - 6) = 0 \\ \\ y = 6 \: or \: 8$

Put the value of y in eq 3

x = 14 - 6 or x = 14 - 8
x = 8 or 6

So that the value of x is 8 or 6 and value of y is 6 or 8


xx + yy

(8)(8) + (6)(6)
= 64 + 36
= 100

Or

(6)(6) + (8)(8)
= 36 + 64
= 100

So that the answer is 100

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#Hope its help