Find (xy + 32)² by using the identities.
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Given that: x + y = 12 and xy = 32 Using the identity, (x + y)^2 = x^2 + 2xy + y^2 (12)^2 = x^2 + 64 + y^2 144 = x^2 + y^2 + 64 144 - 64 = x^2 + y^2 80 ..
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