Math, asked by Vičkëyřock, 1 year ago

Find y if the slope of the line joining (-8,11),(2,y) is -4upon3

Answers

Answered by mysticd

Hi ,

slope of the line joining of ( x1 , y1 ) and ( x2 , y2) is m

m = ( y2 - y1 ) / ( x2 - x1 )

here ,

( x1 , y1 ) = ( -8 , 11 )

( x2 , y2 ) = ( 2 , y )

m = -4 / 3

( y - 11 ) / [ 2 - ( - 8 ) ] = -4 / 3

( y - 11 ) / ( 2 + 8 ) = -4 /3

3( y - 11 ) = ( -4 ) 10

3y - 33 = -40

3y = -40 + 33

3y = -7

y = -7 /3

I hope this helps you.

:)

Vičkëyřock: thnku

ABHAYSTAR: Great!

Anonymous: m = ( y2 - y1 ) / ( x2 - x1 )
( x1 , y1 ) = ( -8 , 11 )
( x2 , y2 ) = ( 2 , y )
m = -4 / 3
( y - 11 ) / [ 2 - ( - 8 ) ] = -4 / 3
( y - 11 ) / ( 2 + 8 ) = -4 /3
3( y - 11 ) = ( -4 ) 10
3y - 33 = -40
3y = -40 + 33
3y = -7
y = -7 /3

ABHAYSTAR: Hmm

Answered by Anonymous

Answer:

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slope= (-11-2)/(8-x)

slope= (-11-2)/(8-x)or, -3/4= -13/(8-x)

slope= (-11-2)/(8-x)or, -3/4= -13/(8-x)or, -24+3x= -52

slope= (-11-2)/(8-x)or, -3/4= -13/(8-x)or, -24+3x= -52or, x = -28/3

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