Question

find y using definition of integration in term of x dy/dx =3x2(square)+2.

Answer 1

Answer:

y = 3x^2/2=2lnx+c

Step-by-step explanation:

x dy/dx = 3x^2+2

dy/dx = 3x + 2/x

dy = 3x + 2/x

integrating on both sides

y = 3x^2/2 + 2lnx + c