Question

find years hence,the age of jacob will be three times that of his son . five years ago ​

Answer 1

Answer:

$\huge\purple {\mathfrak{Bonjour Mate!}}$

Let son's age be x.

Son's age after 5 years.

x + 5

So,

According to given condition ,

Jacobs age = 3(x+5) = 3x+15

His present age = 3x +15 - 5

= 3x+10 ....................... (1)

Five years ago....

Son's age = x - 5

According to the given condition,

Jacobs age = 7(x - 5)

Jacobs age = 7x - 35

His present age = 7x - 35 + 5 =

7x - 30 . . . . . . . .. . . . . . (2)

from(1) \: and \: (2)

3x + 10 = 7x - 30

10 + 30 = 7x - 3x

40 = 4x

x = \frac{40}{4}

x = 10

So,

His sons present age is 10years.

Present age of Jacob=

3x + 10 ...............................from(1)

3(10)+10 = 30 + 10 = 40years.

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Final Answer :

The present ages of Jacob and Son are 40years and 10years.

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Answer 2

Answer:

Jacob's age was seven times of his son. What are their present ages? Therefore Present age of Jacob is 40 years and his son is 10 years.

Step-by-step explanation:

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