Question

find yhe roots of the following equation by factorisation(x+6)(x+2)=x​

Answer 1

Answer:

answer for the given problem is given

Answer 2

Answer :

• Solve for x

(x+6)(x+2)=x

$x^{2}+8x+12=x$

$x^{2}+8x+12-x=0$

$x^{2}+7x+12=0$

$x^{2}+7x=-12$

$x^{2}+7x+\left(\dfrac{7}{2}\right)^{2}=-12+\left(\dfrac{7}{2}\right)^{2}$

$x^{2}+7x+\dfrac{49}{4}=-12+\dfrac{49}{4}$

$x^{2}+7x+\frac{49}{4}=\frac{1}{4}$

$\left(x+\frac{7}{2}\right)^{2}=\frac{1}{4}$

$\sqrt{\left(x+\frac{7}{2}\right)^{2}}=\sqrt{\frac{1}{4}}$

$x+\frac{7}{2}=\frac{1}{2}$

$x+\frac{7}{2}=-\frac{1}{2}$

• x=−3
• x=−4

Thank you !!

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